# Pairing Off

Author: Eric Hodges

http://web.archive.org/web/20080324231941/http://www.microsoft.com/technet/scriptcenter/funzone/games/games08/bevent1.mspx

Event Scenario

This is one of the less-complicated events, both to explain and to perform. In this event we'll be working with a standard deck of playing cards. A standard deck consists of four suits: Hearts, Spades, Clubs, and Diamonds. Within each suit are the numbers two through ten, plus a Jack, a Queen, a King, and an Ace.

Given a random set of five cards, your task is to find out how many pairs are in that set. In other words, if your five cards are the 2 of hearts, the 4 of spades, the 4 of clubs, the queen of diamonds and the queen of spades, you have 2 pairs: 2 fours and 2 queens. As another example, you might have a 3 of clubs, a 3 of diamonds, a 3 of hearts, a 10 of spades and an ace of hearts. In that case you have 3 pairs: 3 of clubs and 3 of diamonds; 3 of diamonds and 3 of hearts; and 3 of clubs and 3 of hearts.

For this event you should assume you've been dealt the following five cards:

• Five of hearts

• Seven of diamonds

• Seven of clubs

• King of clubs

Using this set of cards, your script should display the number of pairs. Keep in mind that we will look at the scripts as we test them. A script that simply displays the number 3 will receive a score of 0; you actually have to do the calculations based on these cards. Not only that, but it shouldn't matter what the cards are: if we substitute any other set of five cards your script should still return the correct number of pairs.

Source code: event001-eric256.pl

```use v6;

my @cards = qw{6 5 6 6 K};
my \$p = 0;
for @cards.kv -> \$k, \$v {
\$p += @cards[\$k+1 .. *].grep: {\$_ eq \$v}
}
say "Total: \$p";

```