# Sum square difference

Author: polettix

https://projecteuler.net/problem=6

The sum of the squares of the first ten natural numbers is,

`1**2 + 2**2 + ... + 10**2 = 385`

The square of the sum of the first ten natural numbers is,

`(1 + 2 + ... + 10)**2 = 55**2 = 3025`

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Source code: prob006-polettix.pl

```use v6;

# Upper bound optionally taken from command line, defaults to
# challenge's request
my \$upper = shift(@*ARGS) || 100;

# This is quite straightforward: the sum of the first N positive
# integers is easily computed as (N + 1) * N / 2, hence the square
# is straightforward. We then subtract the square of each single
# one to get the final result.
my \$result = ((\$upper + 1) * \$upper / 2) ** 2;
\$result -= \$_ ** 2 for 1 .. \$upper;
say \$result;

```